I'm having a hard time trying to figure it out how pulldown a.k.a. resistors to ground work compared to in line resistors. I'm you have a signal, let's say RED on RGB and you add a resistor between signal and plug you get a weaker signal. That's the basic notion of the resistors. But I just founded out that people use resistors to ground and this is called pulldown resistors. If you ground the signal let's say like a T on the wire: RED----plug | GND You'll loose the signal because everything will go to GND. So if you add a resistor you can hold how much signal you want to loose. So my question is, the resistors on a pulldown situation work on the inverse way of a in line resistor? In line: how much higher the resistance weaker and less energy you get on the other side. To ground: how much higher the resistance the stronger the signal because not much is lost to GND (???)
I was trying to understand the same thing. I don't think that they are pull-down resistors. For example a pull-down resistor is to keep a pin of an IC or component low under normal conditions so that it does not float because of interference. What you described is the difference between resistors in series and parallel. With resistors in series the current stays the same though out the whole circuit but the voltage is divided between each resistor depending on thier value. Resistors in parallel are the opposite. The voltage stays the same thought out the whole circuit but the the current will be different at each point in the circuit. Don't take my word for any of this though as this is only the conclusion that I have come to after wondering the same as you. Hopefully someone who knows what they are talking about will be able to answer tis correctly for both of us
There's way too much to explain here.. You have to learn Ohm's law, about voltage sources, and Thevenin's theorem to understand what happens to a signal (generally voltage) through a resistor network.